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7r^2-5r=19
We move all terms to the left:
7r^2-5r-(19)=0
a = 7; b = -5; c = -19;
Δ = b2-4ac
Δ = -52-4·7·(-19)
Δ = 557
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{557}}{2*7}=\frac{5-\sqrt{557}}{14} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{557}}{2*7}=\frac{5+\sqrt{557}}{14} $
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